Get State Name From Drop Down List After Click Submit Button (part 3)

Cont. on Pass city name from php to js (part 2) State data json ($stateJsonObject): Array ( [0] => stdClass Object ( [stateId] => s1 [stateName] => Kuala Lumpur)

Solution 1:

If this is submitted on the same page, you could add the currently submitted entry and put a checked attribute inside the loop:

<form action="test3.php" method="post">
    State:
    <select name="state" id="state" onchange="showCity(this, 'city')">
        <option value ="">select one</option>
        <?php
            for($i = 0; $i < count($stateJsonObject); $i++)
            {
                $selected = ($stateJsonObject[$i]->stateId == $_POST['state']) ? 'checked' : '';
                echo "<option value='".$stateJsonObject[$i]->stateId."' $selected>";
                echo $stateJsonObject[$i] -> stateName;
                echo '</option>';
            }
        ?>
    </select>
    <input type="submit" name="submit" value="Submit" />
</form> 

Or with a foreach variant:

foreach($stateJsonObject as $state) {
    $stateId = $state->stateId;
    $stateName = $state->stateName;
    $selected = ($stateId == $_POST['state']) ? 'checked' : '';
    echo "<option value='$stateId' $selected>$stateName</option>";
}